20x^2+3x+12=0

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Solution for 20x^2+3x+12=0 equation: 



20x^2+3x+12=0

a = 20; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·20·12
Δ = -951
Delta is less than zero, so there is no solution for the equation

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